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  #1  
Old 04-04-2006, 12:06 PM
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Poster Skippy
Can you check this math problem

2/3(x+5)= 1/4(x+2)

my answer is 34/5

6x+8-22x=28+14x-10+12x

my answer is 5/21
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  #2  
Old 04-04-2006, 12:24 PM
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Quote:
Originally Posted by BigWill
Can you check this math problem

2/3(x+5)= 1/4(x+2)

my answer is 34/5
I think it's -34/5
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Old 04-04-2006, 12:27 PM
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thanks
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  #4  
Old 04-04-2006, 12:28 PM
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same thing for the other one.

-5/21
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  #5  
Old 04-04-2006, 01:31 PM
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thanks again
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  #6  
Old 04-04-2006, 01:41 PM
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no problem. math homework?
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  #7  
Old 04-04-2006, 02:14 PM
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Cheater
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Old 04-04-2006, 02:14 PM
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Originally Posted by big pimpin
Cheater
no.
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  #9  
Old 04-04-2006, 03:40 PM
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how bout this Q....Jim is building a recantuglar deck and wants the length to be 3 feet greater than the width. What are the deminsions if the perimeter is 54FT

My Answer is 9 by 6 Feet
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Old 04-04-2006, 04:03 PM
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Quote:
Originally Posted by BigWill
how bout this Q....Jim is building a recantuglar deck and wants the length to be 3 feet greater than the width. What are the deminsions if the perimeter is 54FT

My Answer is 9 by 6 Feet
P = L + W + L + W
P = 2 (L + W)

Since L must be 3' longer than W.....therefore....
L = W + 3

P = 2 [(W + 3) + W]
54 = 2 (2W + 3)
27 = 2W + 3
24 = 2W
W = 12
Therefore.....L = 15' and W = 12'
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  #11  
Old 04-04-2006, 04:06 PM
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Quote:
Originally Posted by BigWill
Can you check this math problem

2/3(x+5)= 1/4(x+2)

my answer is 34/5

6x+8-22x=28+14x-10+12x

my answer is 5/21
Your notation is ambiguous.
Not sure if you mean
(2/3)(x + 5)
or
2/[3(x + 5)]

Use brackets and retype the questions.
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Best Bets Record:
Dec.: 3-0-0 (W3)
Nov.: 2-2-0 (L1)
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  #12  
Old 04-04-2006, 04:06 PM
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thanks
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  #13  
Old 04-04-2006, 04:07 PM
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Quote:
Originally Posted by skippy
Your notation is ambiguous.
Not sure if you mean
(2/3)(x + 5)
or
2/[3(x + 5)]

Use brackets and retype the questions.
its 2/3's like a fraction
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  #14  
Old 04-04-2006, 04:08 PM
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Quote:
Originally Posted by skippy
P = L + W + L + W
P = 2 (L + W)

Since L must be 3' longer than W.....therefore....
L = W + 3

P = 2 [(W + 3) + W]
54 = 2 (2W + 3)
27 = 2W + 3
24 = 2W
W = 12
Therefore.....L = 15' and W = 12'
The Skipster is right. 9X6 would give you an area of 54 but the perimeter is only 30
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  #15  
Old 04-04-2006, 04:10 PM
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Quote:
Originally Posted by dhunter
The Skipster is right. 9X6 would give you an area of 54 but the perimeter is only 30
fuk i knew that problem seemed too easy
thanks
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